比如有 [ 1,5,11,17 ] 索引，现在需要在每个索引元素后面顺序增加两个额外索引元素变为 [ 1,2,3,5,6,7,11,12,13,17,18,19 ]
想过在 dataframe 里增加一个真值列，然后 shift 几次叠加，但是用数量大了以后反复敲 shift 太傻了。。。
一下想不出好办法，求思路
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Supplement 1 · Sep 22, 2020
```
def fuc_a(a, b):
if b == 1:
return a | {i+1 for i in a}
else:
return fuc_a(fuc_a(a,b-1),1)
```
冥思苦想一小时...用集合加递归解决了
def fuc_a(a, b):
if b == 1:
return a | {i+1 for i in a}
else:
return fuc_a(fuc_a(a,b-1),1)
```
冥思苦想一小时...用集合加递归解决了
 |
1
yellowtail OP ```
def fuc_a(a, b): if b == 1: return a | {i+1 for i in a} else: return fuc_a(fuc_a(a,b-1),1) ``` 冥思苦想一小时...用集合加递归解决了 |
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