像这样：
for i in [1,2,3]:
if i==1:
if xxx:
跳过下一次循环，直接进入i=3的情况
for i in [1,2,3]:
if i==1:
if xxx:
跳过下一次循环，直接进入i=3的情况
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This topic created in 4990 days ago, the information mentioned may be changed or developed.
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1
wog Feb 6, 2013
for i in [1,2,3]:
if i==2: conitnue print(i) |
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2
wog Feb 6, 2013
囧continue都拼错了，你改一下吧
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3
BOYPT Feb 6, 2013
不可能。
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4
VYSE Feb 6, 2013 via Android
模仿C循环方式不就行了
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5
yujnln Feb 6, 2013
print [i for i in [1,2,3] if i!=2]
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6
sivacohan Feb 6, 2013
goto~
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7
dotbuddle Feb 6, 2013
列表是不是也有index？
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8
Narcissu5 Feb 7, 2013
用枚举器循环，continue的同时next一下（好像更麻烦的说-_-!）
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9
yuelang85 Feb 7, 2013  2
如果是遍历列表的话，可以remove/pop掉下一个元素
>>> l = [1,2,3,4] >>> for i, v in enumerate(l): ... if v == 2: ... x = l.pop(i+1) ... print v ... 1 2 4 |
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10
yuelang85 Feb 7, 2013
>>> l = [1,2,3,4]
>>> for i, v in enumerate(l): ... ...if v == 2: ... ......x = l.pop(i+1) ... ...print v ... 1 2 4 |
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