listA = [0,1,0,1....0,1] listB = ['A','B','C'....'An','Bn'] 结果是 finallist = ['B','D'...'Bn'] 就是根据 listA 为 1 的值 对应选出 listB 的值，不用 for 循环，怎么写效率最高
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This topic created in 2970 days ago, the information mentioned may be changed or developed.
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1
Inkway Aug 14, 2018  2
finallist = listB[1::2]
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2
vipppppp Aug 15, 2018
思考了一下，觉得还是写 for 循环靠谱。。。
final_list = [a[i] for i in range(min(len(a), len(b))) if b[i] == 1] |
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3
vipppppp Aug 15, 2018
a,b 数组写反了 T_T
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4
mayorbryant Aug 15, 2018
试试
map(lambda y: y[1], filter(lambda x: x[0] == 1, zip(a, b)))  |
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5
mayorbryant Aug 15, 2018
上面那个 == 1 也可以去掉，主要是提醒你，如果想要 0 丢应的，就把 1 换成 0
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6
mayorbryant Aug 15, 2018
当然，如果你的需求只是跳位取值的话，用 list 自带的步长是最简洁的
# 取奇数位 b[1::2] # 取偶数位 b[0::2] |
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